The lack of conservation of energy of the expanding of spacetime of the Universe as noncommutative phase DARK graviton secret of light

 

The photon energy disappeared into the expanding spacetime.

https://www.researchgate.net/post/What_happens_to_the_photon_energy_that_is_lost_to_cosmic_redshift 

So says John A. Macken:

 I am a retired laser physicist. Previously I was the president of two laser related companies which I started. I also recently completed a 9 year term on the St. Mary’s College (California) Board of Trustees. I am an inventor with 36 US patents. My current project proposes the quantum vacuum has the properties of a universal field which can generate all particles, forces and even other fields.

https://www.researchgate.net/publication/280081640_Energetic_Spacetime_the_New_Aether/link/55a6f0b808ae410caa750e0f/download

 Energetic Spacetime: the New Aether

 In addition, all decrease of energy density in Universe is due to the increased pace of time and increased three-dimensional distances, which, however, does not lead to the movement of objects in space, because the speed of the objects in this space is purely peculiar.

Since the objects remain almost stationary in space, the cosmological Doppler effect does not occur. This effect occurs only when the motion of bodies in space.

Thus, in the hypothesis of the Big Bang there is nor the Doppler effect, and nor the loss of energy by photons, and the disappearance of energy in empty space.

http://www.natureoflight.org/CP/

 

 In red shift , gravity does negative work on the photon and In blue shift , gravity does positive work on the photon.

 Do you think photon includes matter and antimatter in its inside ?

 https://www.researchgate.net/post/How_can_a_photon_have_a_frequency_but_not_a_phase

 However, in CPH theory photons are combination of positive and negative virtual photons. Photon is a very weak electric dipole that is consistent with the experience and these articles are asserted. In addition, this property of photon (very weak electric dipole) can describe the absorption and emission energy by charged particles. In additon, a photon is made up of sub quantum energies and frequency of photon is depended to the number of sub quantum energies and interaction between them in structure of photon.

 Robert Shuler

NASA Johnson Space Center

There is the phase of an electromagnetic (EM) wave of which the photon is an energy quantum, and there is the phase of a Schrodinger (or de Broglie) wave that is a complex quantity related to the location of the photon.

It is in the context of de Broglie-Schrodinger waves that the uncertainty principle is valid.  You may have a laser, emitting coherent photons, and you may reduce the intensity of the beam to where only one photon at a time is present, and you may know both the frequency and phase in the EM sense as accurately as you please.  But you still have no idea where individual photons are, or when they will be detected.

The EM frequency of a photon gives its energy level E.  The uncertainty principle holds that we cannot then determine precisely the time of detection of a photon of precisely known frequency but makes no prohibition about phase:  ΔEΔt ≤ ћ/2

On the other hand, the EM phase of a photon (or field) gives precisely its momentum.  For this the uncertainty principle is ΔpΔx ≤ ћ/2 and we find that if we precisely know phase, we have no idea where the photon is.  But there are no restrictions on frequency.

 So, frequency and phase are NOT a quantum conjugate pair.  It is possible that a photon may have ... or not have ... a precisely defined frequency or phase, but measuring one does not disturb the other.

Note that if we construct a measurement to determine the phase of a photon, we will always be able to measure it.  By doing so, we scramble its position, so that it does not have simultaneously precise position and phase (momentum).  However, we may turn around and then attempt to measure the position and we will get an answer to that too, but the phase will be uncertain.  Uncertain, or unknown, does not mean that it does not have a phase.

The experiment I just described is a bit difficult with photons, because you have to absorb at least part of the energy to detect it.  By scattering, you may only absorb a small part, but nonetheless the frequency is a bit changed and by definition it is incoherent with its previous state.  A gamma ray may knock loose a few electrons and continue on as a lower frequency gamma ray, for example, but it's position has been determined.

So the momentum-position experiment cannot be repeated indefinitely without gradually changing the photon into a lower and lower frequency photon.  Usually the conjugate property scrambling is illustrated with spin or polarization, which may be modified several times before detecting and thus destroying the photon.

 https://www.researchgate.net/publication/303988070_Generalization_of_the_Dirac%27s_Equation_and_Sea

 

 

 

 a photon has an uncertain phase does not mean that it has no phase, or that phase is meaningless for a photon. 

So the derivation of de Broglie's Law of Phase Harmony.

Being wavelike falls short of being a classical wave. A single quantum particle (photon included) is neither exactly classical particle, nor exactly classical wave. To form the latter, you need a very large number of photons, and to make it monochromatic and plane, all of them must be in one state (pure ensemble). An attribute of classical monochromatic plane wave is definite phase, which is reflected in

                         E(x, t) = E₀ cos (kx-omega*t+ϕ)          (1).

But for a single particle, we must use instead de Broglie's complex expression 

                         E(x, t) = E₀ exp(i(kx-omega*t+q)),      (2)

and its probabilistic interpretation makes it ambivalent to multiplication by exp(iq') with an arbitrary phase q' (invariance under gauge transformation). As the result, the total phase ϕ=(q+q') automatically becomes indeterminate. This is consistent with ΔnΔϕ≥1 since Δn=0 for a single particle. But for a pure ensemble with n>>1 we can have a non-zero Δn and even make it arbitrarily large in the classical limit. This can bring phase indeterminacy Δϕ down to zero and allow us to get back to the classical wave (1). Neither of these operations affects frequency, so a huge ensemble of photons all in one state makes a classical wave, but a single photon with the same frequency becomes phase-indeterminate. 

https://soundcloud.com/syntalk/tdal-the-darkness-around-light-syntalk

 

podcast

 Why at High Frequency does Gamma photon Almost don't Refract? 

(direct translation)

 aka the higher the frequency of light the more POINT like it becomes....

 

 THE MIRROR OF SPACETIME IS A PHONON ACOUSTIC WAVE