Wednesday, March 4, 2020

Gene's Green Machine Confirmation that it is the Battery lower resistance OHMs that then lowers the Amp Draw of the DC treadmill motor

 Voidisyinyang Voidisyinyang - you are finding exactly what I found, the 12v lead acid battery doesn't absorb very much power (~30-40 watts). Lead acid batteries aren't very efficient with power storage anyway, at about 85% efficiency. That said, I only use lead acid batteries as a buffer and charge/power other devices. Check out my other videos where I power a 32" and 55" smart TVs. During my workouts, I typically charge my laptop using an automotive charger https://amzn.to/2Tpgnt4 which creates about 65 or so watts resistance, along other automotive chargers https://amzn.to/2x2xZC2 to charge a USB-C power pack (13w) an iPad (12w) and a fan (6w) https://amzn.to/2TPFEvx - if I need more resistance, I charge a Lipo battery using this charger iSDT https://amzn.to/2PO00E1 What I like about the iSDT charger is I can change the resistance (amps) mid ride without stopping and starting again, and with the giant 11.1v 177Wh Lipo I just picked up, I can crank the resistance over 150 watts! I then use the charged Lipo to finish charging my iPad, iPhone and portable battery packs. So, in a nutshell - don't bother using lead acid batteries for storage, get your resistance elsewhere with automotive chargers or Lipo chargers. Hope it helps!
 Pedal Generator Charging Various Batteries - vid

 OK this answers my question! Or addresses it - so with that AC/DC converter - for 100 watts. So I get .83 amps. So the resistance is 120/.83 if I'm correct - so that's 144 Ohms. So I expected you to be pedaling a lot slower due to the resistance. But it seems you are pedaling faster to try to get your volts higher to then increase your amp output to power the t.v. But since it's only .83 amps - it appears that it is really the conversion to the higher volts that is the main reason you need to pedal so much faster.... Now I'm going to look for your lithium battery vid. thanks
 powering tvs using a DC/AC inverter - vid

OK I think I follow you now - I'm still fascinated by your 100 watt AC tv experiment - because that should have an ohms of 144 for the AC conversion - but it's only .83 amps? So how come the 144 Ohms resistance doesn't mean you need to pedal slower? Or how do you think - the inversion resistance is still DC? So it's 100/12 = 8 something amps so ohms is 12/8 - so not even 2 ohms. So the resistance must still be DC ohms? Maybe that's why you are pedaling so fast and having trouble getting up to 100 watts. What do you think? thanks.
So based on that assumption - I get .8 ohms via DC power for the DVD player at 180 watts and 1.5 amps. So that's why I can't increase my amps high enough against the watt use draw! Fascinating. I mean I can while just watching the DVD player but not if I have another charger attached.

 https://genesgreenmachine.com/ for building plans


Ok thank you so much for your response confirming that indeed it is the resistance level of the draw that limits the amp output on the treadmill motor. So first of all - that automotive charger has a 4.5 amp output - so you're saying you put that into your lithium battery to increase the load draw? I actually use a 31 Amp-hour lithium battery converter (the Chafon 346 watt-hour). So I also had been wondering about this - because when I powered a 1.5 amp DVD player along with a 50 watt battery charger (for an 18 volt drill) - so I think then the bicycle resistance did go down - but I was only meeting the charging amps as the same level as the draw amp use (so the drill charger draws 1.8 amps). OK I will try that AGAIN and try pedaling faster-harder to increase the amp draw. The thing is that I like to watch movies - instead of trying to power a Toaster at 700 watts - like that German cyclist - have you seen that vid?

So do you know if he is pedaling a DC generator and it is inverting to AC? Because my question for you is - what about the AC resistance when it inverts? For example 700 watts on AC 120 volts - so I think the resistance works out to be an astonishing 19 ohms. Anyway also my lithium battery has a built in charge controller that is the "advanced battery management system" - so I think it can only 6 amps. OK - so you have a smart controller than handles 14 amps. But my guess is your battery has a built in controller? I mean are you just relying on the increased load by hooking up stuff to your lithium battery inverter? I'll watch your vids - if those explain it. I just had to type a response because I find this whole thing fascinating.

So I've read claims that 50% of the power is lost by trying to convert bicycle mechanical energy into electrical charging. The 50% is from resistance but as you say a lead battery is only 85% efficient. So I just got a reply from Pedal-A-Watt and his battery has a smart controller - that is a converter of volts into amps via the bicycle (like a DC-DC buck converter). So he says how the battery resistance goes down as the battery charges up - so that you can fully charge the battery. For me - the final hour of charging is actually just the "balancing" of the voltage levels for each of the 36 cells - so it's at 100% and then the light goes to green after an hour of cell balancing. So my guess is that the cycling resistance will be very low for that. My point is that is the difference between a lithium and lead battery efficient - right? You can fully charge and fully drain the lithium battery without wearing out the cells so easily.

So my real question here is how much resistance increase from the AC conversion? For example I can not power my DVD directly through DC on the lithium battery since it only outputs less than 1 amp per DC output plug - and so I use the AC inverter on the DVD player. So then I wonder how much my resistance is increasing - not due to the amp load (thereby increasing the amps) but simply due to inverting to AC! And so I think if I buy a DC 2.1 mm plug splitter then I can have two DC output plugs going into the one DC female input on the DVD player. But I'm not sure if the female input plug will work as the right size - it's not expensive to try ordering the splitter. I'm just wondering if you think it's worth it to not have that AC inverter increasing the resistance on 1.5 amp output draw.

thanks again

 OK I just tried powering the DVD player directly through the DC-DC buck converter using an AC-DC inverter and then inverting that back to DC for the DVD player. OK - I got no draw. I was hoping the draw would be more - since I'm at 80% on the Chafon lithum battery inverter. So I don't think I can charge as fast - the resistance has lowered too much on the Chafon. Maybe with the DVD player plugged in - it draws it down enough. But it's just about even - at the 80%. So anyway now I discovered that this inverter just doesn't work at all. It was a discontinued item. One hardware store had it priced at $22 and another had it priced at $7. haha. So I guess I gotta drive to Harbor Freight to get the same inverter I had before - only I blew that previous inverter by wiring into it the wrong way. oops. Yes I was trying to answer this same question - about how the resistance changes by inverting to AC power. So if you have any comments on that - I'd appreciate it. thanks.

No comments:

Post a Comment