Perfect timing since I need the multimeter hooked up to adjust the DC/DC buck converter - and I JUST hooked up the multimeter!
So without the DC/DC buck converter - I'm getting too much resistance (meaning my volts are too high to be converts to amps and yet staying under 3 ohms).
So I was working up a sweat big time - since the resistance on the load torque was too high.
I really wanted to downshift - but I didn't want to lose my amps. Also when I converted the multimeter to read the amps - suddenly the battery stopped charging!! Meaning the amp draw on the multimeter was sucking up the charge. oops.
OK so now I disconnected the battery and in the LOWEST gear I'm at 35 volts if I pedal as fast as possible but below thirty - around 28 volts if I take it easy.
So the DC/DC buck converter should now convert those high volts into low volts - and then I can increase the amp output up to 4.5 amps I think (for the standard running current).
I must have done a blog post on this DC/DC buck converter - analyzing the specs. Let's find that....
OK now to review.
I would use a dummy load resistor [connected to the output] to draw the maximum current at the desired voltage. With current pot at maximum, decrease until the [output] voltage drops.So I don't have a "dummy load" because the multimeter will cause too much torque - or maybe the DC/DC buck converter will change the load torque?
Sensorless Load Torque Estimation and Passivity Based Control of ...
I really don't want to read through all that stuff. haha. So back to my blogpost info:An algebraic approach is presented for the fast feed-forward adaptation of the angular velocity trajectory tracking task in a Boost-converter driven dc-motor ...Download Table | Specifications for buck converter fed DC motor. from publication: Sensorless Load Torque Estimation and Passivity Based Control of Buck ...of sensorless load torque estimation for buck converter fed DC motor is shown in Figure 1 in which í µí¼” * is considered as desired speed. Feedback signals V, í ...by L Xheladini - 2015 - Cited by 1 - Related articlesefficiency change as the load is increased. Index Terms — Series/Shunt DC Motor, buck converter, torque, speed, efficiency. I. INTRODUCTION. Recently, the...
Input Voltage:DC 4-30V (limit 36V)So I need to lower the output amps to 5A....
Output Voltage: DC 1.2-30V (adjustable,default 5V)
Minimum Voltage Difference: 1V
Output Current Range: 0-10A (default 6A)
Output Constant Current Range: 0.3-10A
Operating temperature: -40°c to +85°c
Working frequency: 150KHz
Conversion efficiency: up to 98%
Installation: 4x 3mm screws
Wiring: Terminals, Needn't solder, V-IN input, V-OUT output
Cutting size: 60mmx26mm
Have operating indicator
I guess I should increase the volts to 12 volts?
The lithium batteries charge at 3 volts - but the power converter takes up to 18 volts - in the Chafon.
hmmm....
I guess I'll just experiment with the torque load - and see what happens!
I can't measure the Amp current output.
Let's see if the Chafon charges at 6 amp - what happens.
https://elixirfield.blogspot.com/2019/01/5-times-more-power-from-dcdc-buck.html
OK so let's see what I posted there.
It's hard to believe my Treadmill motor could kick out such high amps at so low voltage!! But yesterday I posted someone else doing the same. It's the RESISTANCE that's the issue. That's what this DC/DC buck converter is supposed to fix.... (I hope)...22 volt = 2.75 amps = 60.5 watt12 volt = 5.041 ampsSo above 12 volts.22 volts is maximum with minimum as 12.2 volts
OK back to the Chafon post...2.18 V is the maximum.PER CELL FOR CELL BALANCING - 36 cells. So 97 volts total x 5 amp = 485 watts total storage.Lithium Ion battery
The question is - how does it balance the volts...
- built-in 36 pieces, 3.7 V, 26000 mAh 18650 lithium battery, so the theoretically capacity is 36 * 3.7*2.6 =346.32
O.K. so now we know why typically you want a 5 amp limitation on charging, to spread the 12 volt amps down to 2.7 amps.So what's the resistance again?
I forgot I'm going to have a load on the generator also while I'm charging!
I'll just try it with the presets...
I know it's crazy - so I'll watch for the magic smoke...
OK fine - I'll increase the volts to 12 - just as the factory says - but remember the battery has a load that will pull the voltage down. But that will increase the resistance I guess...
Yeah I don't want to do the math. I'll just experiment.
EXPERIMENT ONE
So I first had to use my fingernail to adjust the voltage. So then I was switching the multimeter between amps and voltage. Amazingly the DC/DC buck converter worked just as it is supposed to!! It was set at 5 volts - preset. Sure enough - the 36 volt max was brought down to 5.6 volts!!! And the amps were over 5 amps! Now keep in mind - this is at the LOWEST bicycle gear - just easy pedaling. Well yes when I switched to amps - since I had "no load" - then there was some resistance - but not as much. There is some kind of load torque by the DC/DC buck converter. So I got way higher amps than ever before - and in the lowest gear, easy cycling!!
So then I keep adjusting the voltage up with my thumb nail and the amps slowly went down as the voltage went up. When I got to about 8 volts - then the amps were under 5 (the limit). So I decided to just try it to see if it would charge. I hooked up the battery - generator - and no charge! So I thought dang I have to increase the volts! So I increased the volts and still no charge. In fact even the volts were not going up! So I switched back to just the multimeter by disconnecting the battery. Then I realized I was still in the "charge" setting - the amps - on the multimeter. So now my voltage was up to 13.4.
That is actually the PERFECT ideal voltage for charging lithium batteries - from what I have read. So then I switched back to the generator. Now as I cycled - the charge light was on. And sure enough the percentage on the charge was going up fast!!! I was cycling in lowest gear and just as the DC/DC buck converter is supposed to do - it tripled my power.
So now I was really excited - and the best test was to see if I could charge the TV (which is 125 watts) plus the DVD player - I mean take the load of those - so 150 watts - while I also charged the battery. So I plugged it all in - and had the TV and DVD player going and as I bicycled. First the load from the extra watts dropped the charge percentage by 10 points. That is what it always does. But as I kept cycling - the charge percentage slowly kept going down. Now I was kind of pissed. My goal was to be able to charge the TV plus the DVD player - and the battery all at the same time.
So the only way to fix this was to lower the voltage on the DC/DC converter - so I get more amps. I figured - since the battery had charged before - this morning - while the load of the battery pulled the voltage down to below 12 - then it should be able to charge at lower voltage.
So I used the thumbnail to keep lowering the voltage. I think I got it back down to about 9 volts. So I figured with the load of the TV/DVD then the amps could be higher the 5 - and it should be enough power to keep charging the battery. So I plugged back in the TV/DVD - and this was my big mistake.
I forgot about the SURGE wattage and since I had used up the battery - the surge wattage is maybe 400 watts - for DVD and TV. But the charge on the battery was below 50% which means I only had 200 watts. So suddenly I heard this loud alarm!!! And sure enough there was a magic smoke smell!
OK so I quickly unplugged the TV/DVD and also one of the wires accidentally disconnected from the DC/DC buck converter. So then I brought the Chafon inside and plugged it into the AC outlet and it is charging fine. So the AC power "works" - at least for charging. I'll have to try plugging in an AC load to see if that works.
OK so I got an AC load and so I reconnected the DC/DC Buck converter. Then I checked the voltage again - and it was at 10 volts - and I checked the amps. So I decided to see if it would charge the Chafon at 10 volts. The charge light did come on but the percentage did not increase and also - the multimeter showed NO load - the voltage did not go down at all even though I was "charging" the battery.
So that made me suspicious - that indeed you do have to be above 12 volts to activate charge. So I increased the voltage again with my thumbnail - so I was at 12.6 volts. This is what I measured above - to be the ideal for greatest charge. I hooked up the battery and sure enough NOW the voltage dropped on the multimeter - so the battery was taking a load. ALSO - suddenly the bicycle was harder to pedal - meaning the load torque of the battery resistance was kicking in!!
So I had just proven indeed you do need to be above the 12 volts to get a charge on the Chafon 500 watt. So then I plugged in the DVD player and watched while I was once again "Chillaxin'" in lowest gear - easy pedaling - and the percentage went up. But I need to experiment more - I had it plugged into the AC outlet - so now it's at 65% or so. So that means the regulator might be lowering the amps it can take in - beyond the "quick charge" rate. So I'll just keep seeing how fast it charges - it didn't charge noticeably faster - not by much. A little bit faster. But it might charge faster when the battery can take a great load with less resistance - at a lower percentage. I'm not sure.
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